public Matrix <double> PseudoInverse(Matrix <double> M)
        {
            var svd = M.Svd(true);
            var W   = svd.W;
            var s   = svd.S;

            // The first element of W has the maximum value.
            double tolerance = Precision.EpsilonOf(2) * Math.Max(M.RowCount, M.ColumnCount) * W[0, 0];

            for (int i = 0; i < s.Count; i++)
            {
                if (s[i] < tolerance)
                {
                    s[i] = 0;
                }
                else
                {
                    s[i] = 1 / s[i];
                }
            }
            W.SetDiagonal(s);

            // (U * W * VT)T is equivalent with V * WT * UT
            return((svd.U * W * svd.VT).Transpose());
        }
Example #2
0
        private static Matrix <double> PseudoInverse(Svd <double> svd)
        {
            Matrix <double> W = svd.W();
            Vector <double> s = svd.S();

            // The first element of W has the maximum value.
            double tolerance = Precision.EpsilonOf(2) * Math.Max(svd.U().RowCount, svd.VT().ColumnCount) * W[0, 0];

            for (int i = 0; i < s.Count; i++)
            {
                if (s[i] < tolerance)
                {
                    s[i] = 0;
                }
                else
                {
                    s[i] = 1 / s[i];
                }
            }

            W.SetDiagonal(s);

            // (U * W * VT)T is equivalent with V * WT * UT
            return((svd.U() * W * svd.VT()).Transpose());
        }
Example #3
0
        /// <summary>
        /// Moore–Penrose pseudoinverse
        /// If A = U • Σ • VT is the singular value decomposition of A, then A† = V • Σ† • UT.
        /// For a diagonal matrix such as Σ, we get the pseudoinverse by taking the reciprocal of each non-zero element
        /// on the diagonal, leaving the zeros in place, and transposing the resulting matrix.
        /// In numerical computation, only elements larger than some small tolerance are taken to be nonzero,
        /// and the others are replaced by zeros. For example, in the MATLAB or NumPy function pinv,
        /// the tolerance is taken to be t = ε • max(m,n) • max(Σ), where ε is the machine epsilon. (Wikipedia)
        /// </summary>
        /// <param name="M">The matrix to pseudoinverse</param>
        /// <returns>The pseudoinverse of this Matrix</returns>
        public static Matrix PseudoInverse(this Matrix M)
        {
            Svd    D = M.Svd(true);
            Matrix W = (Matrix)D.W();
            Vector s = (Vector)D.S();

            // The first element of W has the maximum value.
            double tolerance = Precision.EpsilonOf(2) * Math.Max(M.RowCount, M.ColumnCount) * W[0, 0];


            for (int i = 0; i < s.Count; i++)
            {
                if (s[i] < tolerance)
                {
                    s[i] = 0;
                }
                else
                {
                    s[i] = 1 / s[i];
                }
            }
            W.SetDiagonal(s);

            // (U * W * VT)T is equivalent with V * WT * UT
            return((Matrix)(D.U() * W * D.VT()).Transpose());
        }
Example #4
0
 public override double EpsilonOf(double a)
 {
     return(Precision.EpsilonOf(a));
 }