C# (CSharp) JsonSimple.Deserialize Examples

Example #1

        public void Convert()
        {
            var dict = JsonSimple.Deserialize(jsonSource.Value) as Dictionary <string, object>;


            result.Value = System.Convert.ToString(dict[extract.Value]);



            return;
        }

Example #2

 public void Convert()
 {
     count = 0;
     ParseJSON(0, JsonSimple.Deserialize(jsonSource.Value) as Dictionary <string, object>, ref count);
     return;
 }