public void UnderstandingTheFormula()
{
Dictionary <string, uint> developerToContribution;
double value;
// The higher the number the more "fractalized"
// The more developers the higher the number gets.
// However: Some (very) small contributions make the number smaller.
// 0
developerToContribution = new Dictionary <string, uint> {
{ "A", 100 }
};
value = FractalValue.Calculate(developerToContribution);
Assert.AreEqual(0.0, value);
// 0.5
developerToContribution = new Dictionary <string, uint> {
{ "A", 100 }, { "B", 100 }
};
value = FractalValue.Calculate(developerToContribution);
Assert.AreEqual(0.5, value);
// 0.44
developerToContribution = new Dictionary <string, uint> {
{ "A", 100 }, { "B", 50 }
};
value = FractalValue.Calculate(developerToContribution);
Assert.AreEqual(0.44, Math.Round(value, 2));
// 0.67
developerToContribution = new Dictionary <string, uint> {
{ "A", 100 }, { "B", 100 }, { "C", 100 }
};
value = FractalValue.Calculate(developerToContribution);
Assert.AreEqual(0.67, Math.Round(value, 2));
// 0.625
developerToContribution = new Dictionary <string, uint> {
{ "A", 100 }, { "B", 50 }, { "C", 50 }
};
value = FractalValue.Calculate(developerToContribution);
Assert.AreEqual(0.625, Math.Round(value, 3));
// 0.75
developerToContribution = new Dictionary <string, uint> {
{ "A", 100 }, { "B", 100 }, { "C", 100 }, { "D", 100 }
};
value = FractalValue.Calculate(developerToContribution);
Assert.AreEqual(0.75, Math.Round(value, 2));
// 0.057
developerToContribution = new Dictionary <string, uint> {
{ "A", 100 }, { "B", 1 }, { "C", 1 }, { "D", 1 }
};
value = FractalValue.Calculate(developerToContribution);
Assert.AreEqual(0.057, Math.Round(value, 3));
// 0.46
developerToContribution = new Dictionary <string, uint> {
{ "A", 100 }, { "B", 50 }, { "C", 1 }, { "D", 1 }
};
value = FractalValue.Calculate(developerToContribution);
Assert.AreEqual(0.46, Math.Round(value, 2));
}
public void UnderstandingTheFomrula()
{
Dictionary <string, uint> developerToContribution;
double value;
// The higher the number the more "fractalized"
// The more developers the higher the number gets.
// However: Some (very) small contributions make the number smaller.
// 0
developerToContribution = new Dictionary <string, uint>();
developerToContribution.Add("A", 100);
value = FractalValue.Calculate(developerToContribution);
// 0.5
developerToContribution = new Dictionary <string, uint>();
developerToContribution.Add("A", 100);
developerToContribution.Add("B", 100);
value = FractalValue.Calculate(developerToContribution);
// 0.44
developerToContribution = new Dictionary <string, uint>();
developerToContribution.Add("A", 100);
developerToContribution.Add("B", 50);
value = FractalValue.Calculate(developerToContribution);
// 0.67
developerToContribution = new Dictionary <string, uint>();
developerToContribution.Add("A", 100);
developerToContribution.Add("B", 100);
developerToContribution.Add("C", 100);
value = FractalValue.Calculate(developerToContribution);
// 0.625
developerToContribution = new Dictionary <string, uint>();
developerToContribution.Add("A", 100);
developerToContribution.Add("B", 50);
developerToContribution.Add("C", 50);
value = FractalValue.Calculate(developerToContribution);
// 0.75
developerToContribution = new Dictionary <string, uint>();
developerToContribution.Add("A", 100);
developerToContribution.Add("B", 100);
developerToContribution.Add("C", 100);
developerToContribution.Add("D", 100);
value = FractalValue.Calculate(developerToContribution);
// 0.0057
developerToContribution = new Dictionary <string, uint>();
developerToContribution.Add("A", 100);
developerToContribution.Add("B", 1);
developerToContribution.Add("C", 1);
developerToContribution.Add("D", 1);
value = FractalValue.Calculate(developerToContribution);
// 0.46
developerToContribution = new Dictionary <string, uint>();
developerToContribution.Add("A", 100);
developerToContribution.Add("B", 50);
developerToContribution.Add("C", 1);
developerToContribution.Add("D", 1);
value = FractalValue.Calculate(developerToContribution);
}
public double CalculateFractalValue()
{
return(FractalValue.Calculate(DeveloperToContribution));
}
