internal void CreateInstanceFrom(GraphicsDevice device, EffectData effectData, EffectPool effectPool)
{
GraphicsDevice = device;
ConstantBuffers = new EffectConstantBufferCollection();
Parameters = new EffectParameterCollection();
Techniques = new EffectTechniqueCollection();
Pool = effectPool ?? device.DefaultEffectPool;
// Sets the effect name
Name = effectData.Description.Name;
// Register the bytecode to the pool
var effect = Pool.RegisterBytecode(effectData);
// Initialize from effect
InitializeFrom(effect, null);
// If everything was fine, then we can register it into the pool
Pool.AddEffect(this);
}
/// <summary>
/// Initializes a new instance of the <see cref="Effect" /> class with the specified effect loaded from an effect pool.
/// </summary>
/// <param name="device">The device.</param>
/// <param name="pool">The effect pool.</param>
/// <param name="effectName">Name of the effect.</param>
public Effect(GraphicsDevice device, EffectPool pool, string effectName) : base(device, effectName)
{
ConstantBuffers = new EffectConstantBufferCollection();
Parameters = new EffectParameterCollection();
Techniques = new EffectTechniqueCollection();
ResourceLinker = ToDispose(new EffectResourceLinker());
Pool = pool;
Initialize();
}
/// <summary>
/// Initializes a new instance of the <see cref="Effect" /> class with the specified bytecode effect. See remarks.
/// </summary>
/// <param name="device">The device.</param>
/// <param name="effectData">The bytecode to add to <see cref="GraphicsDevice.DefaultEffectPool"/>. This bytecode must contain only one effect.</param>
/// <exception cref="ArgumentException">If the bytecode doesn't contain a single effect.</exception>
/// <remarks>
/// The effect bytecode must contain only a single effect and will be registered into the <see cref="GraphicsDevice.DefaultEffectPool"/>.
/// </remarks>
public Effect(GraphicsDevice device, EffectData effectData) : base(device)
{
if (effectData.Effects.Count != 1)
throw new ArgumentException(string.Format("Expecting only one effect in the effect bytecode instead of [{0}]. Use GraphicsDevice.DefaultEffectPool.RegisterBytecode instead", Utilities.Join(",", effectData.Effects)), "bytecode");
ConstantBuffers = new EffectConstantBufferCollection();
Parameters = new EffectParameterCollection();
Techniques = new EffectTechniqueCollection();
ResourceLinker = ToDispose(new EffectResourceLinker());
Pool = device.DefaultEffectPool;
// Sets the effect name
Name = effectData.Effects[0].Name;
// Register the bytecode to the pool
Pool.RegisterBytecode(effectData);
Initialize();
}
/// <summary>
/// Initializes a new instance of the <see cref="Effect" /> class with the specified bytecode effect. See remarks.
/// </summary>
/// <param name="device">The device.</param>
/// <param name="effectData">The bytecode to add to the Effect Pool. This bytecode must contain only one effect.</param>
/// <param name="effectPool">The effect pool used to register the bytecode. Default is <see cref="GraphicsDevice.DefaultEffectPool"/>.</param>
/// <exception cref="ArgumentException">If the bytecode doesn't contain a single effect.</exception>
/// <remarks>The effect bytecode must contain only a single effect and will be registered into the <see cref="GraphicsDevice.DefaultEffectPool"/>.</remarks>
public Effect(GraphicsDevice device, EffectData effectData, EffectPool effectPool = null) : base(device)
{
if (effectData.Effects.Count != 1)
throw new ArgumentException(string.Format("Expecting only one effect in the effect bytecode instead of [{0}].", Utilities.Join(",", effectData.Effects)), "effectData");
ConstantBuffers = new EffectConstantBufferCollection();
Parameters = new EffectParameterCollection();
Techniques = new EffectTechniqueCollection();
Pool = effectPool ?? device.DefaultEffectPool;
// Sets the effect name
Name = effectData.Effects[0].Name;
// Register the bytecode to the pool
Pool.RegisterBytecode(effectData);
// Initialize from effect
InitializeFrom(Pool.Find(Name));
// If everything was fine, then we can register it into the pool
Pool.AddEffect(this);
}