C# (CSharp) DialogUtil.GetFilePathByOpenDialog Examples

Example #1

        private void button1_Click(object sender, EventArgs e)
        {
            filePath = DialogUtil.GetFilePathByOpenDialog("图头表设计文件(*.vdml)|*.vdml|dxf文件(*.dxf)|*.dxf|vdcl文件(*.vdcl)|*.vdcl");

            this.tb_ModelFilePath.Text = filePath;
        }

Example #2

File: HyperTxtLinkFrm.cs Project: zhanghang080/Drawlatest

 private void button1_Click(object sender, EventArgs e)
 {
     this.tb_NewLink.Text = DialogUtil.GetFilePathByOpenDialog("");
 }