double MaxLoiNhuan(double a)
{
double t = 0;
if (a <= 1000)
{
t = 1.15;
}
else if (a <= 5000)
{
t = 1.1;
}
else if (a < 100000)
{
t = 1.07;
}
else if (a < 1000000)
{
t = 1.05;
}
else
{
t = 1.02;
}
return(t);
}
