internal static IntegrationSettings SetMultiIntegrationDefaults(IntegrationSettings original, int d)
{
IntegrationSettings settings = new IntegrationSettings();
settings.RelativePrecision = (original.RelativePrecision < 0.0) ? Math.Pow(10.0, -(0.0 + 14.0 / d)) : original.RelativePrecision;
settings.AbsolutePrecision = (original.AbsolutePrecision < 0.0) ? Math.Pow(10.0, -(1.0 + 14.0 / d)) : original.AbsolutePrecision;
settings.EvaluationBudget = (original.EvaluationBudget < 0.0) ? (int)Math.Round(Math.Pow(10.0, 9.0 - 8.0 / d)) : original.EvaluationBudget;
settings.Listener = original.Listener;
return(settings);
}
internal static IntegrationSettings SetIntegrationDefaults(IntegrationSettings settings)
{
IntegrationSettings result = new IntegrationSettings();
result.RelativePrecision = (settings.RelativePrecision < 0.0) ? 1.0E-14 : settings.RelativePrecision;
result.AbsolutePrecision = (settings.AbsolutePrecision < 0.0) ? 1.0E-15 : settings.AbsolutePrecision;
result.EvaluationBudget = (settings.EvaluationBudget < 0) ? 5000 : settings.EvaluationBudget;
result.Listener = settings.Listener;
return(result);
}
/// <summary>
/// Estimates a multi-dimensional integral using the given evaluation settings.
/// </summary>
/// <param name="function">The function to be integrated.</param>
/// <param name="volume">The volume over which to integrate.</param>
/// <param name="settings">The integration settings.</param>
/// <returns>A numerical estimate of the multi-dimensional integral.</returns>
/// <remarks>
/// <para>Note that the integration function must not attempt to modify the argument passed to it.</para>
/// <para>Note that the integration volume must be a hyper-rectangle. You can integrate over regions with more complex boundaries by specifying the integration
/// volume as a bounding hyper-rectangle that encloses your desired integration region, and returing the value 0 for the integrand outside of the desired integration
/// region. For example, to find the volume of a unit d-sphere, you can integrate a function that is 1 inside the unit d-sphere and 0 outside it over the volume
/// [-1,1]<sup>d</sup>. You can integrate over infinite volumes by specifing volume endpoints of <see cref="Double.PositiveInfinity"/> and/or
/// <see cref="Double.NegativeInfinity"/>. Volumes with dimension greater than 15 are not currently supported.</para>
/// <para>Integrals with hard boundaries (like our hyper-sphere volume problem) typically require more evaluations than integrals of smooth functions to achieve the same accuracy.
/// Integrals with canceling positive and negative contributions also typically require more evaluations than integtrals of purely positive functions.</para>
/// <para>Numerical multi-dimensional integration is computationally expensive. To make problems more tractable, keep in mind some rules of thumb:</para>
/// <ul>
/// <li>Reduce the required accuracy to the minimum required. Alternatively, if you are willing to wait longer, increase the evaluation budget.</li>
/// <li>Exploit symmetries of the problem to reduce the integration volume. For example, to compute the volume of the unit d-sphere, it is better to
/// integrate over [0,1]<sup>d</sup> and multiply the result by 2<sup>d</sup> than to simply integrate over [-1,1]<sup>d</sup>.</li>
/// <li>Apply analytic techniques to reduce the dimension of the integral. For example, when computing the volume of the unit d-sphere, it is better
/// to do a (d-1)-dimesional integral over the function that is the height of the sphere in the dth dimension than to do a d-dimensional integral over the
/// indicator function that is 1 inside the sphere and 0 outside it.</li>
/// </ul>
/// </remarks>
/// <exception cref="ArgumentException"><paramref name="function"/>, <paramref name="volume"/>, or <paramref name="settings"/> are null, or
/// the dimension of <paramref name="volume"/> is larger than 15.</exception>
/// <exception cref="NonconvergenceException">The prescribed accuracy could not be achieved with the given evaluation budget.</exception>
public static IntegrationResult Integrate(Func <IList <double>, double> function, IList <Interval> volume, IntegrationSettings settings)
{
if (function == null)
{
throw new ArgumentNullException(nameof(function));
}
if (volume == null)
{
throw new ArgumentNullException(nameof(volume));
}
if (settings == null)
{
throw new ArgumentNullException(nameof(settings));
}
// Get the dimension from the box
int d = volume.Count;
settings = SetMultiIntegrationDefaults(settings, d);
// Translate the integration volume, which may be infinite, into a bounding box plus a coordinate transform.
Interval[] box = new Interval[d];
CoordinateTransform[] map = new CoordinateTransform[d];
for (int i = 0; i < d; i++)
{
Interval limits = volume[i];
if (Double.IsInfinity(limits.RightEndpoint))
{
if (Double.IsInfinity(limits.LeftEndpoint))
{
// -\infinity to +\infinity
box[i] = Interval.FromEndpoints(-1.0, +1.0);
map[i] = new TangentCoordinateTransform(0.0);
}
else
{
// a to +\infinity
box[i] = Interval.FromEndpoints(0.0, 1.0);
map[i] = new TangentCoordinateTransform(limits.LeftEndpoint);
}
}
else
{
if (Double.IsInfinity(limits.LeftEndpoint))
{
// -\infinity to b
box[i] = Interval.FromEndpoints(-1.0, 0.0);
map[i] = new TangentCoordinateTransform(limits.RightEndpoint);
}
else
{
// a to b
box[i] = limits;
map[i] = new IdentityCoordinateTransform();
}
}
}
// Use adaptive cubature for small dimensions, Monte-Carlo for large dimensions.
MultiFunctor f = new MultiFunctor(function);
f.IgnoreInfinity = true;
f.IgnoreNaN = true;
UncertainValue estimate;
if (d < 1)
{
throw new ArgumentException("The dimension of the integration volume must be at least 1.", "volume");
}
else if (d < 4)
{
IntegrationRegion r = new IntegrationRegion(box);
estimate = Integrate_Adaptive(f, map, r, settings);
}
else if (d < 16)
{
estimate = Integrate_MonteCarlo(f, map, box, settings);
}
else
{
throw new ArgumentException("The dimension of the integrtion volume must be less than 16.", "volume");
}
// Sometimes the estimated uncertainty drops precipitiously. We will not report an uncertainty less than 3/4 of that demanded.
double minUncertainty = Math.Max(0.75 * settings.AbsolutePrecision, Math.Abs(estimate.Value) * 0.75 * settings.RelativePrecision);
if (estimate.Uncertainty < minUncertainty)
{
estimate = new UncertainValue(estimate.Value, minUncertainty);
}
return(new IntegrationResult(estimate, f.EvaluationCount, settings));
}
internal IntegrationResult(UncertainValue estimate, int evaluationCount, IntegrationSettings settings) : base(evaluationCount)
{
Debug.Assert(settings != null);
this.estimate = estimate;
this.settings = settings;
}
/// <summary>
/// Evaluates a definite integral with the given evaluation settings.
/// </summary>
/// <param name="integrand">The function to be integrated.</param>
/// <param name="range">The range of integration.</param>
/// <param name="settings">The settings which control the evaluation of the integral.</param>
/// <returns>The result of the integral.</returns>
/// <exception cref="ArgumentNullException">The <paramref name="integrand"/> is <see langword="null"/>.</exception>
/// <exception cref="NonconvergenceException">The maximum number of function evaluations was exceeded before the integral
/// could be determined to the required precision.</exception>
/// <remarks>
/// <para>For information, see <see cref="Integrate(Func{double, double}, double, double, IntegrationSettings)"/>.</para>
/// </remarks>
public static IntegrationResult Integrate(Func <double, double> integrand, Interval range, IntegrationSettings settings)
{
return(Integrate(integrand, range.LeftEndpoint, range.RightEndpoint, settings));
}
/// <summary>
/// Evaluates a definite integral.
/// </summary>
/// <param name="integrand">The function to be integrated.</param>
/// <param name="range">The range of integration.</param>
/// <returns>The result of the integral.</returns>
/// <exception cref="ArgumentNullException">The <paramref name="integrand"/> is <see langword="null"/>.</exception>
/// <exception cref="NonconvergenceException">The maximum number of function evaluations was exceeded before the integral
/// could be determined to the required precision.</exception>
/// <remarks>
/// <para>By default, integrals are evaluated to a relative precision of about 10<sup>-14</sup>, about two digits short of full
/// precision, or an absolute precision of about 10<sup>-16</sup>, using a budget of about 5000 evaluations.
/// To specify different evaluation settings use
/// <see cref="Integrate(Func{double, double}, Interval, IntegrationSettings)"/>.</para>
/// <para>See <see cref="Integrate(Func{double, double}, Interval, IntegrationSettings)"/> for detailed remarks on
/// numerical integration.</para>
/// </remarks>
public static IntegrationResult Integrate(Func <double, double> integrand, Interval range)
{
IntegrationSettings settings = new IntegrationSettings();
return(Integrate(integrand, range, settings));
}
// the public API
/// <summary>
/// Evaluates a definite integral.
/// </summary>
/// <param name="integrand">The function to be integrated.</param>
/// <param name="start">The lower integration endpoint.</param>
/// <param name="end">The upper integration endpoint.</param>
/// <returns>The result of the integral.</returns>
/// <exception cref="ArgumentNullException">The <paramref name="integrand"/> is <see langword="null"/>.</exception>
/// <exception cref="NonconvergenceException">The maximum number of function evaluations was exceeded before the integral
/// could be determined to the required precision.</exception>
/// <remarks>
/// <para>By default, integrals are evaluated to a relative precision of about 10<sup>-14</sup>, about two digits short of full
/// precision, or an absolute precision of about 10<sup>-16</sup>, using a budget of about 5000 evaluations.
/// To specify different evaluation settings use
/// <see cref="Integrate(Func{double, double}, double, double, IntegrationSettings)"/>.</para>
/// <para>See <see cref="Integrate(Func{double, double}, double, double, IntegrationSettings)"/> for detailed remarks on
/// numerical integration.</para>
/// </remarks>
public static IntegrationResult Integrate(Func <double, double> integrand, double start, double end)
{
IntegrationSettings settings = new IntegrationSettings();
return(Integrate(integrand, start, end, settings));
}
// the drivers
private static IntegrationResult Integrate_Adaptive(IAdaptiveIntegrator integrator, IntegrationSettings settings)
{
Debug.Assert(integrator != null);
Debug.Assert(settings != null);
LinkedList <IAdaptiveIntegrator> list = new LinkedList <IAdaptiveIntegrator>();
list.AddFirst(integrator);
int n = integrator.EvaluationCount;
while (true)
{
// go through the intervals, adding estimates (and errors)
// and noting which contributes the most error
// keep track of the total value and uncertainty
UncertainValue vTotal = new UncertainValue();
// keep track of which node contributes the most error
LinkedListNode <IAdaptiveIntegrator> maxNode = null;
double maxError = 0.0;
LinkedListNode <IAdaptiveIntegrator> node = list.First;
while (node != null)
{
IAdaptiveIntegrator i = node.Value;
UncertainValue v = i.Estimate;
vTotal += v;
if (v.Uncertainty > maxError)
{
maxNode = node;
maxError = v.Uncertainty;
}
node = node.Next;
}
// Inform listeners of our latest result.
if (settings.Listener != null)
{
settings.Listener(new IntegrationResult(vTotal, n, settings));
}
// if our error is small enough, return
double tol = settings.ComputePrecision(vTotal.Value);
if (vTotal.Uncertainty <= tol)
{
// Don't claim uncertainty significantly less than tol.
if (vTotal.Uncertainty < tol / 2.0)
{
vTotal = new UncertainValue(vTotal.Value, tol / 2.0);
}
return(new IntegrationResult(vTotal, n, settings));
}
// if our evaluation count is too big, throw
if (n > settings.EvaluationBudget)
{
throw new NonconvergenceException();
}
// Subdivide the interval with the largest error
IEnumerable <IAdaptiveIntegrator> divisions = maxNode.Value.Divide();
foreach (IAdaptiveIntegrator division in divisions)
{
list.AddBefore(maxNode, division);
n += division.EvaluationCount;
}
list.Remove(maxNode);
}
}
/// <summary>
/// Evaluates a definite integral with the given evaluation settings.
/// </summary>
/// <param name="integrand">The function to be integrated.</param>
/// <param name="start">The left integration endpoint.</param>
/// <param name="end">The right integration endpoint.</param>
/// <param name="settings">The settings which control the evaluation of the integral.</param>
/// <returns>The result of the integral.</returns>
/// <remarks>
/// <para>To do integrals over infinite regions, simply set <paramref name="start"/> or <paramref name="end"/>
/// to <see cref="System.Double.NegativeInfinity"/> or <see cref="System.Double.PositiveInfinity"/>.</para>
/// <para>Our integrator handles smooth functions extremely efficiently. It handles integrands with
/// discontinuities or kinks at the price of slightly more evaluations of the integrand.
/// It can handle oscillatory functions, as long as cancelation between positive and negative regions
/// is not too severe. It can integrate logarithmic and mild power-law singularities.</para>
/// <para>Strong power-law singularities will cause the algorithm to fail with a <see cref="NonconvergenceException"/>.
/// This is unavoidable for essentially any double-precision numerical integrator. Consider, for example,
/// the integrable singularity x<sup>-1/2</sup>. Since
/// ε = ∫<sub>0</sub><sup>δ</sup> x<sup>-1/2</sup> dx = 2 δ<sup>1/2</sup>,
/// points within δ ∼ 10<sup>-16</sup> of the end-points, which as a close as you can get to
/// a point in double precision without being on top of it, contribute at the ε ∼ 10<sup>-8</sup>
/// level to our integral, well beyond limit that nearly-full double precision requires. Said differently,
/// to know the value of the integral to ε ∼ 10<sup>-16</sup> precision, we would need to
/// evaluate the contributions of points within δ ∼ 10<sup>-32</sup> of the endpoints,
/// which is far closer than we can get.</para>
/// <para>If you need to evaluate an integral with such a strong singularity, try to make an analytic
/// change of variable to absorb the singularity before attempting numerical integration. For example,
/// to evaluate I = ∫<sub>0</sub><sup>b</sup> f(x) x<sup>-1/2</sup> dx, substitute y = x<sup>1/2</sup>
/// to obtain I = 2 ∫<sub>0</sub><sup>√b</sup> f(y<sup>2</sup>) dy.</para>
/// <para>To do multi-dimensional integrals, use
/// <see cref="MultiFunctionMath.Integrate(Func{IReadOnlyList{double}, double}, IReadOnlyList{Interval}, IntegrationSettings)"/>.
/// </para>
/// </remarks>
/// <exception cref="ArgumentNullException">The <paramref name="integrand"/> is <see langword="null"/>.</exception>
/// <exception cref="NonconvergenceException">The maximum number of function evaluations was exceeded before the integral
/// could be determined to the required precision.</exception>
public static IntegrationResult Integrate(Func <double, double> integrand, double start, double end, IntegrationSettings settings)
{
if (integrand == null)
{
throw new ArgumentNullException(nameof(integrand));
}
if (settings == null)
{
throw new ArgumentNullException(nameof(settings));
}
// Deal with right-to-left integrals
if (end < start)
{
IntegrationResult r = Integrate(integrand, end, start, settings);
return(new IntegrationResult(-r.Estimate, r.EvaluationCount, r.Settings));
}
// Re-map infinite integrals to finite integrals
if (Double.IsNegativeInfinity(start) && Double.IsPositiveInfinity(end))
{
// -\infty to +\infty
// remap to (-\pi/2,\pi/2)
Func <double, double> f1 = delegate(double t) {
double x = Math.Tan(t);
return(integrand(x) * (1.0 + x * x));
};
return(Integrate(f1, -Global.HalfPI, +Global.HalfPI, settings));
}
else if (Double.IsPositiveInfinity(end))
{
// finite to +\infty
// remap to interval (-1,1)
Func <double, double> f1 = delegate(double t) {
double q = 1.0 / (1.0 - t);
double x = start + (1.0 + t) * q;
return(integrand(x) * 2.0 * q * q);
};
return(Integrate(f1, -1.0, +1.0, settings));
}
else if (Double.IsNegativeInfinity(start))
{
// -\infty to finite
// remap to interval (-1,1)
Func <double, double> f1 = delegate(double t) {
double q = t + 1.0;
double x = end + (t - 1.0) / q;
return(integrand(x) * (2.0 / q / q));
};
return(Integrate(f1, -1.0, +1.0, settings));
}
// Fix settings.
settings = SetIntegrationDefaults(settings);
// normal integral over a finite range
Debug.Assert(end >= start);
IAdaptiveIntegrator integrator = new GaussKronrodIntegrator(integrand, Interval.FromEndpoints(start, end));
IntegrationResult result = Integrate_Adaptive(integrator, settings);
return(result);
}
private static UncertainValue Integrate_MonteCarlo(MultiFunctor f, CoordinateTransform[] map, IList <Interval> box, IntegrationSettings settings)
{
int d = box.Count;
// Use a Sobol quasi-random sequence. This give us 1/N accuracy instead of 1/\sqrt{N} accuracy.
//VectorGenerator g = new RandomVectorGenerator(d, new Random(314159265));
VectorGenerator g = new SobolVectorGenerator(d);
// Start with a trivial Lepage grid.
// We will increase the grid size every few cycles.
// My tests indicate that trying to increase every cycle or even every other cycle is too often.
// This makes sense, because we have no reason to believe our new grid will be better until we
// have substantially more evaluations per grid cell than we did for the previous grid.
LePageGrid grid = new LePageGrid(box, 1);
int refineCount = 0;
// Start with a reasonable number of evaluations per cycle that increases with the dimension.
int cycleCount = 8 * d;
//double lastValue = Integrate_MonteCarlo_Cycle(f, map, g, grid, cycleCount);
// Each cycle consists of three sets of evaluations.
// At first I did this with just two set and used the difference between the two sets as an error estimate.
// I found that it was pretty common for that difference to be low just by chance, causing error underestimatation.
double value1 = Integrate_MonteCarlo_Cycle(f, map, g, grid, cycleCount);
double value2 = Integrate_MonteCarlo_Cycle(f, map, g, grid, cycleCount);
double value3 = Integrate_MonteCarlo_Cycle(f, map, g, grid, cycleCount);
while (f.EvaluationCount < settings.EvaluationBudget)
{
// Take the largest deviation as the error.
double value = (value1 + value2 + value3) / 3.0;
double error = Math.Max(Math.Abs(value1 - value3), Math.Max(Math.Abs(value1 - value2), Math.Abs(value2 - value3)));
Debug.WriteLine("{0} {1} {2}", f.EvaluationCount, value, error);
if (settings.Listener != null)
{
settings.Listener(new IntegrationResult(new UncertainValue(value, error), f.EvaluationCount, settings));
}
// Check for convergence.
if ((error <= settings.AbsolutePrecision) || (error <= Math.Abs(value) * settings.RelativePrecision))
{
return(new UncertainValue(value, error));
}
// Do more cycles. In order for new sets to be equal-sized, one of those must be at the current count and the next at twice that.
double smallValue = Integrate_MonteCarlo_Cycle(f, map, g, grid, cycleCount);
cycleCount *= 2;
double bigValue = Integrate_MonteCarlo_Cycle(f, map, g, grid, cycleCount);
// Combine all the cycles into new ones with twice the number of evaluations each.
value1 = (value1 + value2) / 2.0;
value2 = (value3 + smallValue) / 2.0;
value3 = bigValue;
//double currentValue = Integrate_MonteCarlo_Cycle(f, map, g, grid, cycleCount);
//double error = Math.Abs(currentValue - lastValue);
//double value = (currentValue + lastValue) / 2.0;
//lastValue = value;
// Increase the number of evaluations for the next cycle.
//cycleCount *= 2;
// Refine the grid for the next cycle.
refineCount++;
if (refineCount == 2)
{
Debug.WriteLine("Replacing grid with {0} bins after {1} evaluations", grid.BinCount, grid.EvaluationCount);
grid = grid.ComputeNewGrid(grid.BinCount * 2);
refineCount = 0;
}
if (f.EvaluationCount >= settings.EvaluationBudget)
{
throw new NonconvergenceException();
}
}
throw new NonconvergenceException();
}
/// <summary>
/// Evaluates a definite integral with the given evaluation settings.
/// </summary>
/// <param name="integrand">The function to be integrated.</param>
/// <param name="range">The range of integration.</param>
/// <param name="settings">The settings which control the evaulation of the integal.</param>
/// <returns>The result of the integral, which includes an estimated value and an estimated uncertainty of that value.</returns>
/// <exception cref="ArgumentNullException">The <paramref name="integrand"/> is <see langword="null"/>.</exception>
/// <exception cref="NonconvergenceException">The maximum number of function evaluations was exceeded before the integral
/// could be determined to the required precision.</exception>
/// <remarks>
/// <para>To do integrals over infinite regions, simply set the lower bound of the <paramref name="range"/>
/// to <see cref="System.Double.NegativeInfinity"/> or the upper bound to <see cref="System.Double.PositiveInfinity"/>.</para>
/// <para>Our numerical integrator uses a Gauss-Kronrod rule that can integrate efficiently,
/// combined with an adaptive strategy that limits function
/// evaluations to those regions required to achieve the desired accuracy.</para>
/// <para>Our integrator handles smooth functions extremely efficiently. It handles integrands with
/// discontinuities, or discontinuities of derivatives, at the price of slightly more evaluations
/// of the integrand. It can handle oscilatory functions, as long as not too many periods contribute
/// significantly to the integral. It can integrate logarithmic and mild power-law singularities.</para>
/// <para>Strong power-law singularities will cause the alrorighm to fail with a <see cref="NonconvergenceException"/>.
/// This is unavoidable for essentially any double-precision numerical integrator. Consider, for example,
/// the integrable singularity 1/√x. Since
/// ε = ∫<sub>0</sub><sup>δ</sup> x<sup>-1/2</sup> dx = 2 δ<sup>1/2</sup>,
/// points within δ ∼ 10<sup>-16</sup> of the end-points, which as a close as you can get to
/// a point in double precision without being on top of it, contribute at the ε ∼ 10<sup>-8</sup>
/// level to our integral, well beyond limit that nearly-full double precision requires. Said differently,
/// to know the value of the integral to ε ∼ 10<sup>-16</sup> prescision, we would need to
/// evaluate the contributions of points within δ ∼ 10<sup>-32</sup> of the endpoints,
/// which is far closer than we can get.</para>
/// <para>If you need to evaluate an integral with such a strong singularity, make an analytic
/// change of variable to absorb the singularity before attempting numerical integration. For example,
/// to evaluate I = ∫<sub>0</sub><sup>b</sup> f(x) x<sup>-1/2</sup> dx, substitute y = x<sup>1/2</sup>
/// to obtain I = 2 ∫<sub>0</sub><sup>√b</sup> f(y<sup>2</sup>) dy.</para>
/// <para>To do multi-dimensional integrals, use
/// <see cref="MultiFunctionMath.Integrate(Func{IList{double}, double}, IList{Interval}, IntegrationSettings)"/>.
/// </para>
/// </remarks>
public static IntegrationResult Integrate(Func <double, double> integrand, Interval range, IntegrationSettings settings)
{
if (integrand == null)
{
throw new ArgumentNullException(nameof(integrand));
}
if (settings == null)
{
throw new ArgumentNullException(nameof(settings));
}
settings = SetIntegrationDefaults(settings);
// remap infinite integrals to finite integrals
if (Double.IsNegativeInfinity(range.LeftEndpoint) && Double.IsPositiveInfinity(range.RightEndpoint))
{
// -infinity to +infinity
// remap to (-pi/2,pi/2)
Func <double, double> f0 = integrand;
Func <double, double> f1 = delegate(double t) {
double x = Math.Tan(t);
return(f0(x) * (1.0 + x * x));
};
Interval r1 = Interval.FromEndpoints(-Global.HalfPI, Global.HalfPI);
return(Integrate(f1, r1, settings));
}
else if (Double.IsPositiveInfinity(range.RightEndpoint))
{
// finite to +infinity
// remap to interval (-1,1)
double a0 = range.LeftEndpoint;
Func <double, double> f0 = integrand;
Func <double, double> f1 = delegate(double t) {
double q = 1.0 - t;
double x = a0 + (1 + t) / q;
return(f0(x) * (2.0 / q / q));
};
Interval r1 = Interval.FromEndpoints(-1.0, 1.0);
return(Integrate(f1, r1, settings));
}
else if (Double.IsNegativeInfinity(range.LeftEndpoint))
{
// -infinity to finite
// remap to interval (-1,1)
double b0 = range.RightEndpoint;
Func <double, double> f0 = integrand;
Func <double, double> f1 = delegate(double t) {
double q = t + 1.0;
double x = b0 + (t - 1.0) / q;
return(f0(x) * (2.0 / q / q));
};
Interval r1 = Interval.FromEndpoints(-1.0, 1.0);
return(Integrate(f1, r1, settings));
}
// normal integral over a finitite range
IAdaptiveIntegrator integrator = new GaussKronrodIntegrator(integrand, range);
IntegrationResult result = Integrate_Adaptive(integrator, settings);
return(result);
}
