static void Main(string[] args)
{
Stack1 objstack1 = new Stack1();
Stack2 objstack2 = new Stack2();
int input = int.Parse(Console.ReadLine());
for (int i = 0; i < input; i++)
{
string val = Console.ReadLine();
string[] values = val.Split(' ');
if (values[0] == "1")
{
objstack1.push(int.Parse(values[1]));
}
else if (values[0] == "2")
{
int chk;
if (objstack2.empty())
{
while ((chk = objstack1.pop()) != 0)
{
objstack2.push(chk);
}
}
objstack2.pop();
//int chk2;
//while ((chk2= objstack2.pop()) != 0)
//{
// objstack1.push(chk2);
//}
}
else
{
int chk3;
if (objstack2.empty())
{
while ((chk3 = objstack1.pop()) != 0)
{
objstack2.push(chk3);
}
}
Console.WriteLine(objstack2.print());
//int chk4;
//while ((chk4=objstack2.pop() )!= 0)
//{
// objstack1.push(chk4);
//}
}
}
Console.ReadKey();
}
static void dfs(int x, int y, int step)
{
if (x == ex && y == ey)
{
if (step < min)
{
min = step;
ShowPath();
}
return;
}
int tx, ty;
for (int dir = 0; dir < 4; dir++)
{
tx = x + next[dir, 0];
ty = y + next[dir, 1];
if (tx < 0 || tx > map[0].Length - 1 || ty <0 || ty> map.Length - 1)
{
continue;
}
if (map[ty][tx] == 0 && vis[ty, tx] == 0)
{
vis[ty, tx] = 1;
stack.push(new note(tx, ty, stack.top, step + 1)); //加入堆疊
dfs(tx, ty, step + 1);
stack.pop(); // 搜索完畢，移出堆疊
vis[ty, tx] = 0;
}
}
return;
}
static void Main(string[] args)
{
Console.WriteLine("DFS最短步數與路徑搜尋，使用堆疊");
Console.WriteLine("輸入檔案名稱(跟執行檔不同資料夾請輸入絕對路徑)\nEx: maze.txt、maze1.txt、maze2.txt");
path = Console.ReadLine();
text = GetFileText(path);
map = Get2DMap(text, " ", "", new string[] { "\r\n" });
vis = new int[map.Length, map[0].Length];
stack = new Stack2();
Console.WriteLine($"路徑:{path}");
Console.WriteLine($"讀入檔案\n{text}");
Console.WriteLine("讀入陣列");
for (int r = 0; r < map.Length; r++)
{
for (int c = 0; c < map[r].Length; c++)
{
Console.Write(map[r][c]);
}
Console.Write("\n");
}
Console.WriteLine("\n輸入起始位置、終點位置(以空白分隔)EX:0 0 2 3");
temp = Console.ReadLine().Split(' ');
sx = int.Parse(temp[0]); sy = int.Parse(temp[1]);
ex = int.Parse(temp[2]); ey = int.Parse(temp[3]);
// 加入起始位置
vis[sy, sx] = 1;
stack.push(new note(sx, sy, stack.top, 0));
dfs(sx, sy, 0);
Console.WriteLine($"最短步數:{min}");
Console.ReadKey();
}
