Ejemplo n.º 1
0
		/// <summary>
		/// Iterate shapes associated with a given element
		/// </summary>
		/// <param name="modelElement">The parent element to iterate. Can be <see langword="null"/> if <paramref name="shapeElement"/> is specified.</param>
		/// <param name="shapeElement">The shape to reference. Can be <see langword="null"/> if <paramref name="modelElement"/> is specified.</param>
		/// <param name="onePerDiagram">True to filter the shapes to one per diagram</param>
		/// <param name="visitor">A <see cref="Predicate{ShapeElement}"/> callback.
		/// Return <see langword="true"/> to continue iteration.</param>
		public static void VisitAssociatedShapes(ModelElement modelElement, ShapeElement shapeElement, bool onePerDiagram, Predicate<ShapeElement> visitor)
		{
			if (modelElement == null && shapeElement != null)
			{
				modelElement = shapeElement.ModelElement;
			}
			if (modelElement != null)
			{
				LinkedElementCollection<PresentationElement> presentationElements = PresentationViewsSubject.GetPresentation(modelElement);
				int pelCount = presentationElements.Count;
				if (pelCount != 0)
				{
					List<Diagram> visitedDiagrams = null;
					Diagram visitedDiagram = null;

					Partition shapePartition = (shapeElement != null) ? shapeElement.Partition : modelElement.Partition;
					Type thisType = (shapeElement != null) ? shapeElement.GetType() : typeof(ShapeElement);
					for (int i = 0; i < pelCount; ++i)
					{
						PresentationElement pel = presentationElements[i];
						if (shapePartition == pel.Partition && thisType.IsAssignableFrom(pel.GetType()))
						{
							ShapeElement sel = pel as ShapeElement;
							Diagram selDiagram = sel.Diagram;
							if (!onePerDiagram || (visitedDiagram != selDiagram && (visitedDiagrams == null || !visitedDiagrams.Contains(selDiagram))))
							{
								if (!visitor(sel))
								{
									return;
								}
								if (onePerDiagram)
								{
									if (visitedDiagram == null)
									{
										visitedDiagram = selDiagram;
									}
									else
									{
										if (visitedDiagrams == null)
										{
											visitedDiagrams = new List<Diagram>();
										}
										visitedDiagrams.Add(selDiagram);
									}
								}
							}
						}
					}
				}
			}
		}
Ejemplo n.º 2
0
		/// <summary>
		/// Determines if a the model element backing the shape element
		/// is represented by a shape of the same type elsewhere in the presentation
		/// layer. If a derived shape displays multiple presentations, they should
		/// also override the <see cref="DisplaysMultiplePresentations"/> property.
		/// </summary>
		public static bool ElementHasMultiplePresentations(ShapeElement shapeElement)
		{
			ModelElement modelElement;
			if (null != shapeElement &&
				null != (modelElement = shapeElement.ModelElement))
			{
				LinkedElementCollection<PresentationElement> presentationElements = PresentationViewsSubject.GetPresentation(modelElement);
				int pelCount = presentationElements.Count;
				if (pelCount != 0)
				{
					Partition shapePartition = shapeElement.Partition;
					Type thisType = shapeElement.GetType();
					for (int i = 0; i < pelCount; ++i)
					{
						PresentationElement pel = presentationElements[i];
						if (shapeElement != pel && shapePartition == pel.Partition && thisType.IsAssignableFrom(pel.GetType()))
						{
							return true;
						}
					}
				}
			}
			return false;
		}