public void TestGetMedianSingleArray()
{
int[] a = { 2, 1, 3 };
double result = MedianCalculator.GetMedianValue(a);
double expected = 2;
Assert.AreEqual(expected, result);
//even array
a = new int[] { 2, 1, 3, 4, 5, 5 };
result = MedianCalculator.GetMedianValue(a);
expected = 3.5;
Assert.AreEqual(expected, result);
//odd array
a = new int[] { 1, 2, 3, 4, 4, 5, 5 };
result = MedianCalculator.GetMedianValue(a);
expected = 4;
Assert.AreEqual(expected, result);
//even array
a = new int[] { 1, 1, 1, 2, 1, 1, 1, 1 };
result = MedianCalculator.GetMedianValue(a);
expected = 1;
Assert.AreEqual(expected, result);
}
public void TestVeryLargeSourceData3()
{
Random randNumber = new Random();
int[] a = CreateRandomDataSet(randNumber.Next(3, 10000000));
int[] b = { };
double result = MedianCalculator.GetMedianValueHighPerformance(a, b);
int[] combined = a.Concat(b).ToArray();
double expected = MedianCalculator.GetMedianValue(combined);
Assert.AreEqual(expected, result);
}
public void TestGetMedianSingleArray1()
{
int[] a = { 2, 1, 3 };
double result = MedianCalculator.GetMedianValue(a);
double expected = 2;
Assert.AreEqual(expected, result);
a = new int[] { 1, 2, 3, 4 };
int[] b = { 5, 6, 7 };
result = MedianCalculator.GetMedianValueHighPerformance(a, b);
expected = 4;
Assert.AreEqual(expected, result);
}
public void TestVeryLargeSourceData()
{
Random randNumber = new Random();
int[] a = CreateRandomDataSet(randNumber.Next(3, 10000000));
int[] b = CreateRandomDataSet(randNumber.Next(3, 10000000));
//my best guess at how to validate the median, using the previous method and a simple concat.
//I suppose this doesnt have to be efficient if its a test.
double result = MedianCalculator.GetMedianValueHighPerformance(a, b);
int[] combined = a.Concat(b).ToArray();
double expected = MedianCalculator.GetMedianValue(combined);
Assert.AreEqual(expected, result);
}