Ejemplo n.º 1
0
    /**
     * Determine which subcell to select.
     * Combination of intcoord and oldSubindex.
     *
     * @param t the root of the tree
     */
    public int subindex(BTree tree, int l)
    {
        MathVector xp = MathVector.makeMathVector();

        double imxv = (double)Node.IMAX;
        double xsc  = (pos.value(0) - tree.rmin.value(0)) / tree.rsize;

        xp.setValue(0, Math.Floor(imxv * xsc));

        xsc = (pos.value(1) - tree.rmin.value(1)) / tree.rsize;
        xp.setValue(1, Math.Floor(imxv * xsc));

        xsc = (pos.value(2) - tree.rmin.value(2)) / tree.rsize;
        xp.setValue(2, Math.Floor(imxv * xsc));

        int i = 0;

        for (int k = 0; k < MathVector.NDIM; k++)
        {
            if (((int)xp.value(k) & l) != 0)            //This used val & 1 != 0 so if there is a problem look here
            {
                i += Cell.NSUB >> (k + 1);
            }
        }
        return(i);
    }
Ejemplo n.º 2
0
    /**
     * Compute integerized coordinates.
     *
     * @return the coordinates or null if rp is out of bounds
     */
    public MathVector intcoord(MathVector vp)
    {
        MathVector xp = MathVector.makeMathVector();

        double imxv = (double)Node.IMAX;
        double xsc  = (vp.value(0) - rmin.value(0)) / rsize;

        if (0.0 <= xsc && xsc < 1.0)
        {
            xp.setValue(0, Math.Floor(imxv * xsc));
        }
        else
        {
            return(null);
        }

        xsc = (vp.value(1) - rmin.value(1)) / rsize;
        if (0.0 <= xsc && xsc < 1.0)
        {
            xp.setValue(1, Math.Floor(imxv * xsc));
        }
        else
        {
            return(null);
        }

        xsc = (vp.value(2) - rmin.value(2)) / rsize;
        if (0.0 <= xsc && xsc < 1.0)
        {
            xp.setValue(2, Math.Floor(imxv * xsc));
        }
        else
        {
            return(null);
        }

        return(xp);
    }