public void ShowInstrumentRecorderDialog(InstrumentAudioRecorderViewModel viewModel) =>
new InstrumentAudioRecorderDialog
{
DataContext = viewModel
}
.ShowDialog();
public void ShowInstrumentRecorderDialog(InstrumentAudioRecorderViewModel viewModel)
{
var recorder = new InstrumentAudioRecorderDialog {
DataContext = viewModel
};
// Ugly hack: we can't bind DialogResult to the ViewModel in XAML, so let's just do it here.
viewModel.PropertyChanged += (sender, args) =>
{
if (args.PropertyName == nameof(viewModel.RecordedAudio))
{
recorder.DialogResult = true;
}
};
recorder.ShowDialog();
}
