/// <summary>
/// this method check the segments for been common for two parcels
/// </summary>
/// <param name="seg">segment to check</param>
/// <param name="j">number of segment in array</param>
private void DuplicatedSegment(BorderSegment seg, int i)
{
for (int j = 0; j < listOfSegments.Count; j++)
{
if ((j != i) && (((BorderSegment)listOfSegments[i]).Name() == seg.Name()))
{
listOfSegments[j] = null;
}
}
}
/// <summary>
/// This method performs the check about whether current border segment was already added to the array of border segments
/// </summary>
/// <param name="num">number of segment whitch should be checked</param>
/// <returns></returns>
private bool CheckForDuplicatesSegments(BorderSegment seg)
{
bool index = false;
foreach (BorderSegment item in listOfSegments)
{
if ((seg.Name() == ((BorderSegment)item).Name()))
{
index = true;
}
}
return(index);
}
/// <summary>
/// this method returns the cadastral number of the parcel which is right to the segment
/// </summary>
/// <param name="currentSegment">the current segment</param>
/// <returns>cadastral number of a right parcel</returns>
private string ReturnRightParcelNumber(BorderSegment currentSegment)
{
for (int i = 0; i < listOfParcels.Count; i++)
{
for (int j = 0; j < ((Parcel)listOfParcels[i]).GetNumber; j++)
{
if ((((Parcel)listOfParcels[i]).ReturnSegment(j).Name() == currentSegment.Name()) && (((Parcel)listOfParcels[i]).ReturnSegment(j).LeftOrNot == false))
{
return(Convert.ToString(((Parcel)listOfParcels[i]).CadastralNum));
}
}
}
return("");
}