Beispiel #1
0
   /**
     * Returns a random simple digraph on {@code V} vertices, {@code E}
     * edges and (at least) {@code c} strong components. The vertices are randomly
     * assigned integer labels between {@code 0} and {@code c-1} (corresponding to 
     * strong components). Then, a strong component is creates among the vertices
     * with the same label. Next, random edges (either between two vertices with
     * the same labels or from a vetex with a smaller label to a vertex with a 
     * larger label). The number of components will be equal to the number of
     * distinct labels that are assigned to vertices.
     *
     * @param V the number of vertices
     * @param E the number of edges
     * @param c the (maximum) number of strong components
     * @return a random simple digraph on {@code V} vertices and
               {@code E} edges, with (at most) {@code c} strong components
     * @throws IllegalArgumentException if {@code c} is larger than {@code V}
     */
    public static Digraph strong(int V, int E, int c) {
        if (c >= V || c <= 0)
            throw new IllegalArgumentException("Number of components must be between 1 and V");
        if (E <= 2*(V-c))
            throw new IllegalArgumentException("Number of edges must be at least 2(V-c)");
        if (E > (long) V*(V-1) / 2)
            throw new IllegalArgumentException("Too many edges");

        // the digraph
        Digraph G = new Digraph(V);

        // edges added to G (to avoid duplicate edges)
        SET<Edge> set = new SET<Edge>();

        int[] label = new int[V];
        for (int v = 0; v < V; v++)
            label[v] = StdRandom.uniform(c);

        // make all vertices with label c a strong component by
        // combining a rooted in-tree and a rooted out-tree
        for (int i = 0; i < c; i++) {
            // how many vertices in component c
            int count = 0;
            for (int v = 0; v < G.V(); v++) {
                if (label[v] == i) count++;
            }

            // if (count == 0) System.err.println("less than desired number of strong components");

            int[] vertices = new int[count];
            int j = 0;
            for (int v = 0; v < V; v++) {
                if (label[v] == i) vertices[j++] = v;
            }
            StdRandom.shuffle(vertices);

            // rooted-in tree with root = vertices[count-1]
            for (int v = 0; v < count-1; v++) {
                int w = StdRandom.uniform(v+1, count);
                Edge e = new Edge(w, v);
                set.add(e);
                G.addEdge(vertices[w], vertices[v]);
            }

            // rooted-out tree with root = vertices[count-1]
            for (int v = 0; v < count-1; v++) {
                int w = StdRandom.uniform(v+1, count);
                Edge e = new Edge(v, w);
                set.add(e);
                G.addEdge(vertices[v], vertices[w]);
            }
        }

        while (G.E() < E) {
            int v = StdRandom.uniform(V);
            int w = StdRandom.uniform(V);
            Edge e = new Edge(v, w);
            if (!set.contains(e) && v != w && label[v] <= label[w]) {
                set.add(e);
                G.addEdge(v, w);
            }
        }

        return G;
    }