public static Vector3 Lerp(BezierCurveQuadV3D curve, float time)
{
var posOne = Lerps.Lerp(curve.StartPos, curve.MidPos, time);
var posTwo = Lerps.Lerp(curve.MidPos, curve.EndPos, time);
return(posOne + ((posTwo - posOne) * time));
}
public static Vector2 Lerp(Vector2 value1, Vector2 value2, Vector2 value3, float time)
{
var posOne = Lerps.Lerp(value1, value2, time);
var posTwo = Lerps.Lerp(value2, value3, time);
return(posOne + ((posTwo - posOne) * time));
}
public static Vector3 Lerp(Vector3 value1, Vector3 value2, Vector3 value3, Vector3 value4, float time)
{
var posOne = Lerps.Lerp(value1, value2, time);
var posTwo = Lerps.Lerp(value2, value3, time);
var posThree = Lerps.Lerp(value3, value4, time);
posOne = Lerps.Lerp(posOne, posTwo, time);
posTwo = Lerps.Lerp(posOne, posThree, time);
return(posOne + ((posTwo - posOne) * time));
}
public static Vector3 Lerp(BezierCurveV3D curve, float time)
{
switch (curve.Positions.Count)
{
case 0:
return(Vector3.zero);
case 1:
return(curve.Positions[0]);
case 2:
return(Lerps.Lerp(curve.Positions[0], curve.Positions[1], time));
case 3:
return(Lerp(curve.Positions[0], curve.Positions[1], curve.Positions[2], time));
case 4:
return(Lerp(curve.Positions[0], curve.Positions[1], curve.Positions[2], curve.Positions[3], time));
case 5:
return(Lerp(curve.Positions[0], curve.Positions[1], curve.Positions[2], Lerps.Lerp(curve.Positions[3], curve.Positions[4], time), time));
}
//FROM HERE IS IS SAFE
//For there to be at leat 5 hard coded positions
int count = curve.Positions.Count;
var posOne = Lerps.Lerp(curve.Positions[0], curve.Positions[1], time);
var posTwo = Lerps.Lerp(curve.Positions[1], curve.Positions[2], time);
var posThree = Lerps.Lerp(curve.Positions[2], curve.Positions[3], time);
for (var i = 4; i < count - 1; i++)
{
posOne = Lerps.Lerp(posOne, posTwo, time);
posTwo = Lerps.Lerp(posTwo, posThree, time);
posThree = Lerps.Lerp(curve.Positions[i], curve.Positions[i + 1], time);
}
posOne = Lerps.Lerp(posOne, posTwo, time);
posTwo = Lerps.Lerp(posTwo, posThree, time);
return(posOne + ((posTwo - posOne) * time));
}