Beispiel #1
0
        /// <summary>
        /// 判断点与直线的关系,假设你站在a点朝向b点,
        /// 则输入点与直线的关系分为:Left, Right or Centered on the line
        /// </summary>
        /// <param name="point">判断点</param>
        /// <returns>判断结果</returns>
        public PointSide ClassifyPoint(Vector2 point)
        {
            if (point == this.m_cStartPoint || point == this.m_cEndPoint)
            {
                return(PointSide.ON_LINE);
            }
            //向量a
            Vector2 vectorA = this.m_cEndPoint - this.m_cStartPoint;
            //向量b
            Vector2 vectorB = point - this.m_cStartPoint;

            float crossResult = NMath.CrossProduct(vectorA, vectorB);

            if (NMath.IsEqualZero(crossResult))
            {
                return(PointSide.ON_LINE);
            }
            else if (crossResult < 0)
            {
                return(PointSide.RIGHT_SIDE);
            }
            else
            {
                return(PointSide.LEFT_SIDE);
            }
        }
Beispiel #2
0
 /// <summary>
 /// 删除重复顶点
 /// </summary>
 /// <returns></returns>
 public void DelRepeatPoint()
 {
     for (int i = 0; i < this.m_lstPoints.Count; i++)
     {
         for (int j = i + 1; j < this.m_lstPoints.Count; j++)
         {
             if (NMath.IsEqualZero(this.m_lstPoints[i] - this.m_lstPoints[j]))
             {
                 this.m_lstPoints.Remove(this.m_lstPoints[j]);
                 j = i;
             }
         }
     }
 }
Beispiel #3
0
        /// <summary>
        /// 生成最终的路径点
        /// </summary>
        /// <param name="startPos">起始点</param>
        /// <param name="endPos">终点</param>
        /// <param name="triPathList">三角形路径列表</param>
        /// <param name="wayPoints">路径点</param>
        /// <param name="offSet">移动物体宽度</param>
        /// <returns></returns>
        private PathResCode CreateWayPoints(Vector2 startPos, Vector2 endPos
                                            , List <NavTriangle> triPathList, out List <Vector2> wayPoints, int offSet)
        {
            wayPoints = new List <Vector2>();
            if (triPathList.Count == 0 || startPos == null || endPos == null)
            {
                return(PathResCode.Failed);
            }

            // 保证从起点到终点的顺序
            triPathList.Reverse();

            // 保存出边编号
            for (int i = 0; i < triPathList.Count; i++)
            {
                NavTriangle tri = triPathList[i];
                if (i != triPathList.Count - 1)
                {
                    NavTriangle nextTri = triPathList[i + 1];
                    tri.SetOutWallIndex(tri.GetWallIndex(nextTri.GetID()));
                }
            }

            wayPoints.Add(startPos);

            //起点与终点在同一三角形中
            if (triPathList.Count == 1)
            {
                wayPoints.Add(endPos);
                return(PathResCode.Success);
            }

            WayPoint way = new WayPoint(startPos, triPathList[0]);

            while (!NMath.IsEqualZero(way.GetPoint() - endPos))
            {
                way = GetFurthestWayPoint(way, triPathList, endPos, offSet);
                if (way == null)
                {
                    return(PathResCode.CanNotGetNextWayPoint);
                }
                wayPoints.Add(way.GetPoint());
            }

            return(PathResCode.Success);
        }
Beispiel #4
0
        /// <summary>
        /// 两条线段是否相等
        /// </summary>
        /// <param name="lineTemp">判断对象</param>
        /// <returns>是否相等</returns>
        public bool Equals(Line2D line)
        {
            //只是一个点
            if (NMath.IsEqualZero(line.m_cStartPoint - line.m_cEndPoint) ||
                NMath.IsEqualZero(m_cStartPoint - m_cEndPoint))
            {
                return(false);
            }

            //whatever the direction
            bool bEquals = NMath.IsEqualZero(m_cStartPoint - line.m_cStartPoint) ? true : NMath.IsEqualZero(m_cStartPoint - line.m_cEndPoint);

            if (bEquals)
            {
                bEquals = NMath.IsEqualZero(m_cEndPoint - line.m_cStartPoint) ? true : NMath.IsEqualZero(m_cEndPoint - line.m_cEndPoint);
            }
            return(bEquals);
        }
        /// <summary>
        /// 判断这条线段是否没有和其他的边相交
        /// </summary>
        /// <param name="sPnt"></param>
        /// <param name="point"></param>
        /// <returns></returns>
        private bool IsVisibleIn2Point(Vector2 sPnt, Vector2 ePnt)
        {
            Line2D  line = new Line2D(sPnt, ePnt);
            Vector2 interPos;

            foreach (Line2D edge in allEdges)
            {
                if (edge.Intersection(line, out interPos) == LineCrossState.CROSS)
                {
                    if (!NMath.IsEqualZero(sPnt - interPos) &&
                        !NMath.IsEqualZero(ePnt - interPos))
                    {
                        return(false);
                    }
                }
            }
            return(true);
        }
Beispiel #6
0
        /// <summary>
        /// 返回三角形的外接圆
        /// </summary>
        /// <param name="p1"></param>
        /// <param name="p2"></param>
        /// <param name="p3"></param>
        /// <returns></returns>
        public static Circle CreateCircle(Vector2 p1, Vector2 p2, Vector2 p3)
        {
            if (!NMath.IsEqualZero(p1.y - p2.y) ||
                !NMath.IsEqualZero(p2.y - p3.y))
            {
                double yc, xc;
                float  m1  = -(p2.x - p1.x) / (p2.y - p1.y);
                float  m2  = -(p3.x - p2.x) / (p3.y - p2.y);
                double mx1 = (p1.x + p2.x) / 2.0;
                double mx2 = (p2.x + p3.x) / 2.0;
                double my1 = (p1.y + p2.y) / 2.0;
                double my2 = (p2.y + p3.y) / 2.0;

                if (NMath.IsEqualZero(p1.y - p2.y))
                {
                    xc = (p2.x + p1.x) / 2.0;
                    yc = m2 * (xc - mx2) + my2;
                }
                else if (NMath.IsEqualZero(p3.y - p2.y))
                {
                    xc = (p3.x + p2.x) / 2.0;
                    yc = m1 * (xc - mx1) + my1;
                }
                else
                {
                    xc = (m1 * mx1 - m2 * mx2 + my2 - my1) / (m1 - m2);
                    yc = m1 * (xc - mx1) + my1;
                }

                double dx   = p2.x - xc;
                double dy   = p2.y - yc;
                double rsqr = dx * dx + dy * dy;
                double r    = Math.Sqrt(rsqr);

                return(new Circle(new Vector2((float)xc, (float)yc), (float)r));
            }
            return(new Circle(new Vector2(0, 0), 0));
        }
Beispiel #7
0
        /// <summary>
        /// 计算两条二维线段的交点
        /// </summary>
        /// <param name="other">Other line</param>
        /// <param name="intersectPoint">输出的线段交点</param>
        /// <returns>返回值说明了两条线段的位置关系(COLINE,PARALLEL,CROSS,NOT_CROSS) </returns>
        public LineCrossState Intersection(Line2D other, out Vector2 intersectPoint)
        {
            intersectPoint.x = intersectPoint.y = float.NaN;
            if (!NMath.CheckCross(this.m_cStartPoint, this.m_cEndPoint, other.m_cStartPoint, other.m_cEndPoint))
            {
                return(LineCrossState.NOT_CROSS);
            }

            double A1, B1, C1, A2, B2, C2;

            A1 = this.m_cEndPoint.y - this.m_cStartPoint.y;
            B1 = this.m_cStartPoint.x - this.m_cEndPoint.x;
            C1 = this.m_cEndPoint.x * this.m_cStartPoint.y - this.m_cStartPoint.x * this.m_cEndPoint.y;

            A2 = other.m_cEndPoint.y - other.m_cStartPoint.y;
            B2 = other.m_cStartPoint.x - other.m_cEndPoint.x;
            C2 = other.m_cEndPoint.x * other.m_cStartPoint.y - other.m_cStartPoint.x * other.m_cEndPoint.y;

            if (NMath.IsEqualZero(A1 * B2 - B1 * A2))
            {
                if (NMath.IsEqualZero((A1 + B1) * C2 - (A2 + B2) * C1))
                {
                    return(LineCrossState.COLINE);
                }
                else
                {
                    return(LineCrossState.PARALLEL);
                }
            }
            else
            {
                intersectPoint.x = (float)((B2 * C1 - B1 * C2) / (A2 * B1 - A1 * B2));
                intersectPoint.y = (float)((A1 * C2 - A2 * C1) / (A2 * B1 - A1 * B2));
                return(LineCrossState.CROSS);
            }
        }