| public EdgeIndex ( TriangulationPoint p1, TriangulationPoint p2 ) : int | ||
| p1 | TriangulationPoint | |
| p2 | TriangulationPoint | |
| return | int | |
private static bool IsEdgeSideOfTriangle(DelaunayTriangle triangle, PolygonPoint ep, PolygonPoint eq)
{
int index = triangle.EdgeIndex(ep, eq);
if (index == -1)
{
return(false);
}
triangle.MarkConstrainedEdge(index);
triangle = triangle.Neighbors[index];
if (triangle != null)
{
triangle.MarkConstrainedEdge(ep, eq);
}
return(true);
}
/// <summary>
/// After a flip we have two triangles and know that only one will still be
/// intersecting the edge. So decide which to contiune with and legalize the other
/// </summary>
/// <param name="tcx"></param>
/// <param name="o">should be the result of an TriangulationUtil.orient2d( eq, op, ep )</param>
/// <param name="t">triangle 1</param>
/// <param name="ot">triangle 2</param>
/// <param name="p">a point shared by both triangles</param>
/// <param name="op">another point shared by both triangles</param>
/// <returns>returns the triangle still intersecting the edge</returns>
private static DelaunayTriangle NextFlipTriangle(DTSweepContext tcx, Orientation o, DelaunayTriangle t,
DelaunayTriangle ot, PolygonPoint p,
PolygonPoint op)
{
int edgeIndex;
if (o == Orientation.CCW)
{
// ot is not crossing edge after flip
edgeIndex = ot.EdgeIndex(p, op);
ot.EdgeIsDelaunay[edgeIndex] = true;
Legalize(tcx, ot);
ot.EdgeIsDelaunay.Clear();
return(t);
}
// t is not crossing edge after flip
edgeIndex = t.EdgeIndex(p, op);
t.EdgeIsDelaunay[edgeIndex] = true;
Legalize(tcx, t);
t.EdgeIsDelaunay.Clear();
return(ot);
}
