Beispiel #1
0
 public void getParentList(List <SceneProcedure> parentList)
 {
     // 由于父节点列表中需要包含自己,所以先加入自己
     parentList.Add(this);
     // 再加入父节点的所有父节点
     mParentProcedure?.getParentList(parentList);
 }
Beispiel #2
0
    // 获得自己和otherProcedure的共同的父节点
    public SceneProcedure getSameParent(SceneProcedure otherProcedure)
    {
        // 获得两个流程的父节点列表
        LIST(out List <SceneProcedure> tempList0);
        LIST(out List <SceneProcedure> tempList1);
        getParentList(tempList0);
        otherProcedure.getParentList(tempList1);
        // 从前往后判断,找到第一个相同的父节点
        int count0 = tempList0.Count;

        for (int i = 0; i < count0; ++i)
        {
            var thisParent = tempList0[i];
            int count1     = tempList1.Count;
            for (int j = 0; j < count1; ++j)
            {
                if (thisParent == tempList1[j])
                {
                    UN_LIST(tempList0);
                    UN_LIST(tempList1);
                    return(thisParent);
                }
            }
        }
        UN_LIST(tempList0);
        UN_LIST(tempList1);
        return(null);
    }
Beispiel #3
0
    // 获得自己和otherProcedure的共同的父节点
    public SceneProcedure getSameParent(SceneProcedure otherProcedure)
    {
        // 获得两个流程的父节点列表
        List <SceneProcedure> tempList0 = mListPool.newList(out tempList0);
        List <SceneProcedure> tempList1 = mListPool.newList(out tempList1);

        getParentList(ref tempList0);
        otherProcedure.getParentList(ref tempList1);
        // 从前往后判断,找到第一个相同的父节点
        foreach (var thisParent in tempList0)
        {
            foreach (var otherParent in tempList1)
            {
                if (thisParent == otherParent)
                {
                    mListPool.destroyList(tempList0);
                    mListPool.destroyList(tempList1);
                    return(thisParent);
                }
            }
        }
        mListPool.destroyList(tempList0);
        mListPool.destroyList(tempList1);
        return(null);
    }
Beispiel #4
0
 public void getParentList(ref List <SceneProcedure> parentList)
 {
     // 由于父节点列表中需要包含自己,所以先加入自己
     parentList.Add(this);
     // 再加入父节点的所有父节点
     if (mParentProcedure != null)
     {
         mParentProcedure.getParentList(ref parentList);
     }
 }
Beispiel #5
0
    // 获得自己和otherProcedure的共同的父节点
    public SceneProcedure getSameParent(SceneProcedure otherProcedure)
    {
        // 获得两个流程的父节点列表
        List <SceneProcedure> thisParentList  = new List <SceneProcedure>();
        List <SceneProcedure> otherParentList = new List <SceneProcedure>();

        getParentList(ref thisParentList);
        otherProcedure.getParentList(ref otherParentList);
        // 从前往后判断,找到第一个相同的父节点
        foreach (var thisParent in thisParentList)
        {
            foreach (var otherParent in otherParentList)
            {
                if (thisParent == otherParent)
                {
                    return(thisParent);
                }
            }
        }
        return(null);
    }