/// <summary>
 /// Performs the inverse transfrom from a single coordinate of linear units to the same coordinate in geodetic units
 /// </summary>
 /// <param name="xy">The double linear input x and y values organized into a 1 dimensional array</param>
 /// <param name="lp">The double geodetic output lambda and phi values organized into a 1 dimensional array</param>
 /// <param name="startIndex">The zero based integer start index</param>
 /// <param name="numPoints">The integer count of the number of xy pairs in the lp and xy arrays</param>
 protected override void EllipticalInverse(double[] xy, double[] lp, int startIndex, int numPoints)
 {
     for (int i = startIndex; i < startIndex + numPoints; i++)
     {
         int phi = i * 2 + PHI;
         int lam = i * 2 + LAMBDA;
         int x   = i * 2 + X;
         int y   = i * 2 + Y;
         lp[phi] = MeridionalDistance.AngularDistance(_ml0 + xy[y] / K0, Es, _en);
         if (Math.Abs(lp[phi]) >= HALF_PI)
         {
             lp[phi] = xy[y] < 0 ? -HALF_PI : HALF_PI;
             lp[lam] = 0;
         }
         else
         {
             double sinphi = Math.Sin(lp[phi]);
             double cosphi = Math.Cos(lp[phi]);
             double t      = Math.Abs(cosphi) > 1e-10 ? sinphi / cosphi : 0;
             double n      = _esp * cosphi * cosphi;
             double con;
             double d = xy[x] * Math.Sqrt(con = 1 - Es * sinphi * sinphi) / K0;
             con *= t;
             t   *= t;
             double ds = d * d;
             lp[phi] -= (con * ds / (1 - Es)) * FC2 * (1 -
                                                       ds * FC4 * (5 + t * (3 - 9 * n) + n * (1 - 4 * n) -
                                                                   ds * FC6 * (61 + t * (90 - 252 * n +
                                                                                         45 * t) + 46 * n
                                                                               - ds * FC8 * (1385 + t * (3633 + t * (4095 + 1574 * t))))));
             lp[lam] = d * (FC1 -
                            ds * FC3 * (1 + 2 * t + n -
                                        ds * FC5 * (5 + t * (28 + 24 * t + 8 * n) + 6 * n
                                                    - ds * FC7 * (61 + t * (662 + t * (1320 + 720 * t)))))) / cosphi;
         }
     }
 }
Beispiel #2
0
 /// <summary>
 ///
 /// </summary>
 /// <param name="arg"></param>
 /// <param name="es"></param>
 /// <param name="en"></param>
 /// <returns></returns>
 public static double InvMlfn(double arg, double es, double[] en)
 {
     return(MeridionalDistance.AngularDistance(arg, es, en));
 }