private void Open_Click(object sender, EventArgs e)
 {
     if (openFileDialog.ShowDialog() == DialogResult.OK)
     {
         try
         {
             FileArr2 file = new FileArr2(openFileDialog.FileName);
             int[,] Arr2 = file.ReadArr2();
             DataGridViewUtils.Array2ToGrid(Input, Arr2);
         }
         catch (Exception ex)
         {
             MessageBox.Show(ex.Message, "ошибка");
         }
     }
 }
Beispiel #2
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        static int[,] FileReadArr2(string Path)
        {
            FileArr2 file = new FileArr2(Path);

            return(file.ReadArr2());
        }