Beispiel #1
0
        static void Main(string[] args)
        {
            var HW = Console.ReadLine().Split(' ').Select(c => int.Parse(c)).ToList();
            var H  = HW[0];
            var W  = HW[1];
            var A  = Enumerable.Range(0, H).Select(_ => Console.ReadLine().Split(' ').Select(c => int.Parse(c)).ToList()).ToList();

            if (A.SelectMany(AH => AH.Where(AHW => AHW == 5)).Count() == 0 && !(A.All(AH => AH.All(AHW => AHW == 0))))
            {
                // 全て0でなく、5が一つもない場合 ×
                Console.WriteLine("No");
            }
            else if ((H == 1 && A[0][0] != 5 && A[0][W - 1] != 5) || (W == 1 && A[0][0] != 5 && A[H - 1][0] != 5))
            {
                // 1列または1行で、端に5がない(=真ん中に5があり非連結な領域が2つある状態)
                List <int> A1;
                var        length = 0;
                if (H == 1)
                {
                    A1     = A[0]; // 1行
                    length = W;
                }
                else
                {
                    A1     = A.Select(AH => AH[0]).ToList(); // 1列
                    length = H;
                }
                var fiveIndexs   = Enumerable.Range(1, length - 2).Where(i => A1[i] == 5).ToList();
                var maxs         = fiveIndexs.Select(i => solve(A1.Take(i + 1)) + solve(A1.Skip(i))).ToList();
                var maxFiveIndex = fiveIndexs[Enumerable.Range(0, fiveIndexs.Count()).OrderBy(i => maxs[i]).First()];

                Console.WriteLine(solve(A1.Take(maxFiveIndex + 1)) + solve(A1.Skip(maxFiveIndex)) - 1);
            }
            else
            {
                Console.WriteLine("Yes " + solve(A.SelectMany(AH => AH)));    // 2次元配列を1次元に
            }
        }