示例#1
0
        /// <summary>
        /// Returns the value of the density function of a copula, given two input cumulative distribution fucntions, u and v.
        /// </summary>
        public static double CopulaDensityFunction(CopulaType type, double u, double v, double alpha)
        {
            CheckCopulaAlpha(type, alpha);

            switch (type)
            {
                case CopulaType.Clayton:
                    return (1.0 + alpha) * Math.Pow(u * v, -alpha - 1.0) * Math.Pow(Math.Pow(u, -alpha) + Math.Pow(v, -alpha) - 1.0, -1.0 / alpha - 2.0);
                case CopulaType.FGM:
                    return 1.0 + alpha * (1.0 - 2.0 * u) * (1.0 - 2.0 * v);
                case CopulaType.Frank:
                    double d1 = FrankPart(u, alpha) * FrankPart(v, alpha) + FrankPart(1, alpha);
                    return -alpha * FrankPart(1, alpha) * Math.Exp(-alpha * (u + v)) / (d1 * d1);
                case CopulaType.Gumbel:
                    double lnu = Math.Log(u);
                    double lnv = Math.Log(v);
                    double g1 = Math.Pow(lnu * lnv, alpha - 1.0) / (u * v);
                    double g2 = CopulaCumulativeDistributionFunction(type, u, v, alpha);
                    double g3 = Math.Pow(-lnu + -lnv, 1.0 / alpha - 2.0);
                    double g4 = alpha - 1.0 + Math.Pow(-lnu + -lnv, 1.0 / alpha);
                    return g1 * g2 * g3 * g4;
                case CopulaType.Independent:
                    return 1.0;
                case CopulaType.Joe:
                    double ju = Math.Pow(1.0 - u, alpha);
                    double jv = Math.Pow(1.0 - v, alpha);
                    double d3 = ju + jv - ju * jv;
                    return Math.Pow(1.0 - u, alpha - 1.0) * Math.Pow(1.0 - v, alpha) * Math.Pow(d3, (1.0 / alpha) - 2.0) * (1.0 - alpha - d3);
                default:
                    throw new ArgumentException("Copula type not expected.");
            }
        }
示例#2
0
        /// <summary>
        /// Returns the value of a copula, given two input cumulative distribution fucntions, u and v.
        /// </summary>
        public static double CopulaCumulativeDistributionFunction(CopulaType type, double u, double v, double alpha)
        {
            CheckCopulaAlpha(type, alpha);

            switch (type)
            {
                case CopulaType.Clayton:
                    return Math.Pow(Math.Pow(u, -alpha) + Math.Pow(v, -alpha) - 1.0, -1.0 / alpha);
                case CopulaType.FGM:
                    return u * v * (1.0 + alpha * (1.0 - u) * (1.0 - v));
                case CopulaType.Frank:
                    double d1 = 1 + (FrankPart(u, alpha) * FrankPart(v, alpha)) / FrankPart(1.0, alpha);
                    return -(1.0/alpha) * Math.Log(d1);
                case CopulaType.Gumbel:
                    double d2 = -Math.Pow(Math.Pow(-Math.Log(u), alpha) + Math.Pow(-Math.Log(v), alpha), 1.0 / alpha);
                    return Math.Exp(d2);
                case CopulaType.Independent:
                    return u * v;
                case CopulaType.Joe:
                    double ju = Math.Pow(1.0 - u, alpha);
                    double jv = Math.Pow(1.0 - v, alpha);
                    double d3 = ju + jv - ju * jv;
                    return 1 - Math.Pow(d3, 1.0 / alpha);
                default:
                    throw new ArgumentException("Copula type not expected.");
            }
        }
示例#3
0
 private static void CheckCopulaAlpha(CopulaType type, double alpha)
 {
     switch (type)
     {
         case CopulaType.Clayton:
             if (alpha <= 0.0) throw new ArgumentException("Invalid alpha. Alpha should be greater than zero.");
             return;
         case CopulaType.FGM:
             if (alpha < -1.0 || alpha > 1.0) throw new ArgumentException("Invalid alpha. Should be: -1 <= alpha <= +1.");
             return;
         case CopulaType.Frank:
             if (alpha == 0.0) throw new ArgumentException("Invalid alpha. Alpha cannot equal zero.");
             return;
         case CopulaType.Gumbel:
             if (alpha < 1.0) throw new ArgumentException("Invalid alpha. Should be: alpha >= 1.");
             return;
         case CopulaType.Independent:
             return; //no alpha for independent
         case CopulaType.Joe:
             if (alpha < 0.0) throw new ArgumentException("Invalid alpha. Should be: alpha >= 0.");
             return;
         default:
             throw new ArgumentException("Copula type not expected.");
     }
 }
示例#4
0
        /// <summary>
        /// Returns the inverse of the first marginal CDF of a copula, for two cumulative distribution fucntions, u and v.
        /// Used in Monte Carlo simulation.
        /// </summary>
        /// <param name="type"></param>
        /// <param name="u">random number [0-1]</param>
        /// <param name="C1">random number [0-1], independent of u</param>
        /// <param name="alpha"></param>
        /// <returns>v, random number [0-1]</returns>
        public static double CopulaFirstMarginalInverse(CopulaType type, double u, double C1, double alpha)
        {
            CheckCopulaAlpha(type, alpha);

            switch (type)
            {
                case CopulaType.Clayton:
                    double d = Math.Pow(C1, -alpha / (1.0 + alpha)) + Math.Pow(u, alpha) - 1.0;
                    return u * Math.Pow(d, -1.0 / alpha);
                case CopulaType.Frank:
                    double f1 = C1 * (Math.Exp(-alpha) - 1.0);
                    double f2 = 1.0 + (Math.Exp(-alpha * u) - 1.0) * (1.0 - C1);
                    return -(1.0 / alpha) * Math.Log(1.0 + f1 / f2);
                case CopulaType.Independent:
                    return C1;
                default:
                    throw new ArgumentException("Copula type not expected.");
            }
        }