/// <summary>
/// 发牌
/// </summary>
public static void deal()
{
PokerGroup player2Pokers = new PokerGroup();
PokerGroup player3Pokers = new PokerGroup();
player1.pokers.Clear();
for (int i = 0; i < 17; i++)
{
player1.pokers.Add(allPoker[i]);
}
for (int i = 17; i < 34; i++)
{
player2Pokers.Add(allPoker[i]);
}
for (int i = 34; i < 51; i++)
{
player3Pokers.Add(allPoker[i]);
}
LandLordNum = new Random().Next(1, 4);
PokerGroup landLordPokers = new PokerGroup();
for (int i = 51; i < 54; i++)
{
landLordPokers.Add(allPoker[i]);
}
LandLordPokers = landLordPokers;
player1.sort();
if (server.SendDataForClient("StartPokers", player2Pokers, 1) && server.SendDataForClient("StartPokers", player3Pokers, 2))
{
DConsole.Write("[系统消息]发牌成功!");
server.SendOrder(LandLordNum);
}
//if (server.SendDataForClient(player2.pokers, 1) && server.SendDataForClient(player3.pokers, 2))
//{
// DConsole.Write("[系统消息]发牌成功!");
// server.SendOrder(DConsole.LandLordNum);
//}
else
{
DConsole.Write("[系统消息]发牌失败!");
}
#if DEBUG //调试时在Console上显示的信息
Console.WriteLine("玩家一的牌");
foreach (Poker onePoker in player1.pokers)
{
Console.WriteLine(onePoker.pokerColor.ToString() + onePoker.ToString());
}
#endif
}
/// <summary>
/// 对飞机和飞机带翅膀进行排序,把飞机放在前面,翅膀放在后面.
/// </summary>
/// <param name="PG">牌组</param>
/// <returns>是否为连续三张牌</returns>
public static PokerGroup SameThreeSort(PokerGroup PG)
{
Poker FourPoker = null; //如果把4张当三张出并且带4张的另外一张,就需要特殊处理,这里记录出现这种情况的牌的点数.
bool FindedThree = false; //已找到三张相同的牌
PokerGroup tempPokerGroup = new PokerGroup(); //记录三张相同的牌
int count = 0; //记录在连续三张牌前面的翅膀的张数
int Four = 0; // 记录是否连续出现三三相同,如果出现这种情况则表明出现把4张牌(炸弹)当中的三张和其他牌配成飞机带翅膀,并且翅膀中有炸弹牌的点数.
// 比如有如下牌组: 998887777666 玩家要出的牌实际上应该为 888777666带997,但是经过从大到小的排序后变成了998887777666 一不美观,二不容易比较.
for (int i = 2; i < PG.Count; i++) //直接从2开始循环,因为PG[0],PG[1]的引用已经存储在其他变量中,直接比较即可
{
if (PG[i] == PG[i - 2] && PG[i] == PG[i - 1]) // 比较PG[i]与PG[i-1],PG[i]与PG[i-2]是否同时相等,如果相等则说明这是三张相同牌
{
if (Four >= 1) //默认的Four为0,所以第一次运行时这里为false,直接执行else
//一旦连续出现两个三三相等,就会执行这里的if
{
FourPoker = PG[i]; //当找到四张牌时,记录下4张牌的点数
Poker changePoker;
for (int k = i; k > 0; k--) //把四张牌中的一张移动到最前面.
{
changePoker = PG[k];
PG[k] = PG[k - 1];
PG[k - 1] = changePoker;
}
count++; //由于此时已经找到三张牌,下面为count赋值的程序不会执行,所以这里要手动+1
}
else
{
Four++; //记录本次循环,因为本次循环找到了三三相等的牌,如果连续两次找到三三相等的牌则说明找到四张牌(炸弹)
tempPokerGroup.Add(PG[i]); //把本次循环的PG[i]记录下来,即记录下三张牌的点数
}
FindedThree = true; //标记已找到三张牌
}
else
{
Four = 0; //没有找到时,连续找到三张牌的标志Four归零
if (!FindedThree) //只有没有找到三张牌时才让count增加.如果已经找到三张牌,则不再为count赋值.
{
count = i - 1;
}
}
}
foreach (Poker tempPoker in tempPokerGroup) //迭代所有的三张牌点数
{
Poker changePoker; //临时交换Poker
for (int i = 0; i < PG.Count; i++) //把所有的三张牌往前移动
{
if (PG[i] == tempPoker) //当PG[i]等于三张牌的点数时
{
if (PG[i] == FourPoker) //由于上面已经把4张牌中的一张放到的最前面,这张牌也会与tempPoker相匹配所以这里进行处理
// 当第一次遇到四张牌的点数时,把记录四张牌的FourPoker赋值为null,并中断本次循环.由于FourPoker已经为Null,所以下次再次遇到四张牌的点数时会按照正常情况执行.
{
FourPoker = null;
continue;
}
changePoker = PG[i - count];
PG[i - count] = PG[i];
PG[i] = changePoker;
}
}
}
return(PG);
}