コード例 #1
0
ファイル: Employee.cs プロジェクト: anuragbhd/code
 /* The overloading method must be defined within the same class whose
  * objects are going to be used with the operator; else, compiler will complain:
  * One of the parameters of a binary operator must be the containing type. */
 /* It is possible to use any kind of operators inside an overloaded operator
  * besides itself to perform manipulations on variables. */
 /* Overloading + implicitly overloads += also. */
 // Overloading the + operator
 public static Employee operator +(Employee emp_1, Employee emp_2)
 {
     Employee emp = new Employee();
     emp.name = emp_1.name + " " + emp_2.name;
     emp.salary = emp_1.salary + emp_2.salary;
     return emp;
 }
コード例 #2
0
ファイル: Program.cs プロジェクト: anuragbhd/code
 static void Main(string[] args)
 {
     Employee emp_1 = new Employee();
     Employee emp_2 = new Employee();
     Employee emp_3 = new Employee();
     System.Console.Write("Enter name of employee 1: ");
     emp_1.name = System.Console.ReadLine();
     System.Console.Write("Enter salary of employee 1: ");
     emp_1.salary = Convert.ToInt32(System.Console.ReadLine());
     System.Console.Write("\nEnter name of employee 2: ");
     emp_2.name = System.Console.ReadLine();
     System.Console.Write("Enter salary of employee 2: ");
     emp_2.salary = Convert.ToInt32(System.Console.ReadLine());
     emp_3 = emp_1 + emp_2;
     System.Console.WriteLine("\n\nWhen we apply + on the two objects of Employee class, result is -\n");
     System.Console.WriteLine("Name: {0}", emp_3.name);
     System.Console.WriteLine("Salary: {0}", emp_3.salary);
     System.Console.ReadLine();
 }