Esempio n. 1
0
    static object Solve()
    {
        var(n, k) = Read2();
        var s = Console.ReadLine();

        var r = new List <char>();

        var comp = Comparer2 <int> .Create(i => s[i], i => i);

        var set = new IndexedMultiSet <int>(comp);

        for (int i = 0; i < n - k; i++)
        {
            set.Add(i);
        }

        var t = -1;

        for (int i = n - k; i < n; i++)
        {
            set.Add(i);
            while (set.GetFirst() < t)
            {
                set.RemoveAt(0);
            }

            t = set.RemoveAt(0);
            r.Add(s[t]);
        }

        return(string.Join("", r));
    }
Esempio n. 2
0
        public ImmutableArray <T> Sort(Comparison <T> comparison)
        {
            Requires.NotNull(comparison, nameof(comparison));

            var self = this;

            return(self.Sort(Comparer2 <T> .Create(comparison)));
        }
            public void Sort(Comparison <T> comparison)
            {
                Requires.NotNull(comparison, nameof(comparison));

                if (Count > 1)
                {
                    // Array.Sort does not have an overload that takes both bounds and a Comparison.
                    // We could special case _count == _elements.Length in order to try to avoid
                    // the IComparer allocation, but the Array.Sort overload that takes a Comparison
                    // allocates such an IComparer internally, anyway.
                    Array.Sort(_elements, 0, _count, Comparer2 <T> .Create(comparison));
                }
            }
Esempio n. 4
0
    static void Main()
    {
        var n  = int.Parse(Console.ReadLine());
        var ss = Array.ConvertAll(new bool[n], _ => Console.ReadLine());

        var comp = Comparer2 <string> .Create(s => s.TrimStart('0').Length, s => s.TrimStart('0'), s => - s.Length);

        var set = new IndexedMultiSet <string>(comp);

        foreach (var s in ss)
        {
            set.Add(s);
        }

        Console.WriteLine(string.Join("\n", set));
    }