Example #1
0
File: JWD.cs Project: hong1975/wats
 public static JWD GetJWDB(JWD A, double distance, double angle)
 {
     double dx = distance*1000 * Math.Sin(angle * Math.PI /180.0);
       double dy = distance*1000 * Math.Cos(angle * Math.PI /180.0);
       double BJD = (dx/A.Ed + A.m_RadLo) * 180.0/Math.PI;
       double BWD = (dy/A.Ec + A.m_RadLa) * 180.0/Math.PI;
       JWD B = new JWD(BJD, BWD);
       return B;
 }
Example #2
0
File: JWD.cs Project: hong1975/wats
        //! 计算点A 和 点B的经纬度,求他们的距离和点B相对于点A的方位
        /*!
          * \param A A点经纬度
          * \param B B点经纬度
          * \param angle B相对于A的方位, 不需要返回该值,则将其设为空
          * \return A点B点的角度
          */
        public static double angle(JWD A, JWD B)
        {
            double dx = (B.m_RadLo - A.m_RadLo) * A.Ed;
              double dy = (B.m_RadLa - A.m_RadLa) * A.Ec;
              double angle = 0.0;
               angle = Math.Atan(Math.Abs(dx/dy))*180.0/Math.PI;
               // 判断象限
               double dLo = B.m_Longitude - A.m_Longitude;
               double dLa = B.m_Latitude - A.m_Latitude;

               if(dLo > 0 && dLa <= 0) {
             angle = (90.0 - angle) + 90.0;
            }
               else if(dLo <= 0 && dLa < 0) {
             angle = angle + 180.0;
            }
               else if(dLo < 0 && dLa >= 0) {
             angle = (90.0 - angle) + 270;
            }
              return angle;
        }
Example #3
0
File: JWD.cs Project: hong1975/wats
 //! 已知点A经纬度,根据B点据A点的距离,和方位,求B点的经纬度
 /*!
   * /param longitude 已知点A经度
   * /param latitude 已知点A纬度
   * /param distance B点到A点的距离
   * /param angle B点相对于A点的方位
   * /return B点的经纬度坐标
   */
 public static JWD GetJWDB(double longitude, double latitude, double distance, double angle)
 {
     JWD A = new JWD(longitude, latitude);
     return GetJWDB(A, distance, angle);
 }