private IEnumerable<VB6SourceFile> ParseSourceItems(IEnumerable<string> names, VB6SourceFileType sourceFileType)
{
if (names == null) return Enumerable.Empty<VB6SourceFile>();
return names.Select(s => ParseSourceItem(s, sourceFileType));
}
private VB6SourceFile ParseSourceItem(string name, VB6SourceFileType sourceFileType)
{
var result = new VB6SourceFile();
// If the name is in two parts split by a semi-colon or comma, that is the name and fileName
var parts = name.Split(new[] {";", ","}, StringSplitOptions.RemoveEmptyEntries);
result.Type = sourceFileType;
switch (parts.Length)
{
case 1:
result.Name = Path.GetFileNameWithoutExtension(parts[0]);
result.FileName = parts[0];
break;
case 2:
result.Name = parts[0];
result.FileName = parts[1];
break;
default:
throw new ArgumentException("The source item name has too many parts (expecting 1 or 2 parts). Name: " + name, "name");
}
return result;
}
